即日起在codingBlog上分享您的技术经验即可获得积分,积分可兑换现金哦。

HDU3746 Cyclic Nacklace(KMP+最小循环节)

编程语言 dlnumk 13℃ 0评论
本文目录
[隐藏]

1.Cyclic Nacklace

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)


Total Submission(s): 8812    Accepted Submission(s): 3795







Problem Description
CC always becomes very depressed at the end of this month, he has checked his credit card yesterday, without any surprise, there are only 99.9 yuan left. he is too distressed and thinking about how to tide over the last days. Being
inspired by the entrepreneurial spirit of “HDU CakeMan”, he wants to sell some little things to make money. Of course, this is not an easy task.





As Christmas is around the corner, Boys are busy in choosing christmas presents to send to their girlfriends. It is believed that chain bracelet is a good choice. However, Things are not always so simple, as is known to everyone, girl’s fond of the colorful
decoration to make bracelet appears vivid and lively, meanwhile they want to display their mature side as college students. after CC understands the girls demands, he intends to sell the chain bracelet called CharmBracelet. The CharmBracelet is made up with
colorful pearls to show girls’ lively, and the most important thing is that it must be connected by a cyclic chain which means the color of pearls are cyclic connected from the left to right. And the cyclic count must be more than one. If you connect the leftmost
pearl and the rightmost pearl of such chain, you can make a CharmBracelet. Just like the pictrue below, this CharmBracelet’s cycle is 9 and its cyclic count is 2:






Now CC has brought in some ordinary bracelet chains, he wants to buy minimum number of pearls to make CharmBracelets so that he can save more money. but when remaking the bracelet, he can only add color pearls to the left end and right end of the chain, that
is to say, adding to the middle is forbidden.


CC is satisfied with his ideas and ask you for help.
 


Input
The first line of the input is a single integer T ( 0 < T <= 100 ) which means the number of test cases.


Each test case contains only one line describe the original ordinary chain to be remade. Each character in the string stands for one pearl and there are 26 kinds of pearls being described by ‘a’ ~’z’ characters. The length of the string Len: ( 3 <= Len <= 100000 ).
 


Output
For each case, you are required to output the minimum count of pearls added to make a CharmBracelet.
 


Sample Input
3 aaa abca abcde
 


Sample Output
0 2

5

思路 这道题就是只要求出最小循环节就可以解决;

我们知道求最小循环节的方法是求出next数组然后 最小循环节长度就是 len-next[len];

#include 
#include 
#include
using namespace std;

char s[100005];
int Next[100005];
int len;

void getnext()
{
 len = strlen(s);
 Next[0] = Next[1] = 0;
 int i;
 for(i = 1;i




转载请注明:CodingBlog » HDU3746 Cyclic Nacklace(KMP+最小循环节)

喜欢 (0)or分享 (0)
发表我的评论
取消评论

*

表情